RCC SLAB ROOF DESIGN EXAMPLE

                                         R.C.C slab roof 6mx3mx0.12m

 R.C.C work 1:2:4: in footing excluding steel and it’s bending.

= 6.3x3.3x0.12 (0.15m in both sides)

= 2.495 cum

Steel reinforcing bars including bending-

Main bars:  12mm dia @0.89kg/m straight bars

24cm c/c . No (6.3-0.08)/24+1( side covers=2x4cm)

= 27Nos.

L=3.3-2covers+2hooks  (Take cover 4cm, hook 9xd

= 3.3-(2x4cm)+(2x9x12mm )

= 3.44m

27Nosx3.44x0.89 =82.66kg

Bent up bars: 26 Nos 12 mm dia @0.89kg/m

= 3.44m+0.08( add one depth)

= 3.52m

26Nosx3.52x0.89 =81.45kg

Distribution bars:  6mm dia  @0.22 kg/m

           Bottom bars central portion 18cm c/c

(No.= 2.00/0.18+1=12 Nos

Bottom bars 2x3 two sides

Top bars two sides 2x3

Total No of bars = 12+2x3+2x3= 24Nos

L=6.3-2covers+2hooks  (Take cover 4cm, hook 9xd

= 6.3-(2x4cm)+(2x9x6mm )

= 6.33m

24Nosx6.33x0.22=33.42kg

Total steel = 82.66+81.45+33.42

=197.53Kg

ABSTRACT :

1.     R.C.C work 1:2:4: in beam excluding    2.495cum

steel and it’s bending

2.     Steel reinforcing bars including bending-   197.53kg 

 3     Centering & shuttering required:

Area of centering and shuttering

=6mx3m

=18sqm

   

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RCC COLUMN WITH FOUNDATION

                    

                                             R.C.C Column design

Earthwork in excavation in foundation:

1x2.00x2.00x0.83= 3.32CUM

(0.75M trapezoidal portion height+0.08M concrete)

 Cement concrete 1:4:8 in base:

            1x2.00x2.00x0.08= 0.32CUM

 R.C.C work 1:2:4: in footing excluding steel and it’s bending.

Bottom square portion

1x2.00x2.00x0.25= 1.00CUM

Trapezoidal portion Vol

h/6(A1+A2+4Am)

0.5/6{(2x2+.35x.35+4[(2+.35)/2]x[(2+.35)/2]}=0.804CUM

Total : 1.00+0.804= 1.804CUM

R.C.C work 1:2:4: in column above Ground Level (G.L) excluding steel and it’s bending

Square portion below plinth level (P.L)

1x.35x.35x60 = 0.074 CUM

Circular portion above plinth level

1x(π/4x0.30x0.30)x3.30 = 0.233 CUM

Total:  0.074+0.233 = 0.307 CUM

Steel reinforcing bars including bending-

(i)                12 mm dia bars @0.89kg in base footing

No. of bars = (200cm-8cm)/15cm+1= 14Nos.

(Bars are spaced at 15cm  centre to centre and cover 8cm less, 4cm in one side + 1 bar is added)

L=200-2covers+2hooks = 200-2x4+2x9x1.2 = 213.6cm,  say 2.14m

(cover=4cm, hook = 9xd, d is diameter of bar 12mm = 1.2cm)

Bars are placed two way so

2x14Nos.x2.14m (Bar length) = 2x14x2.14 = 53.33 Kg.

(ii)              16mm diameter dowel bars@ 1.58 kg    

L= 0.45+0.75-2xcover+bend on the concrete

= 0.45+0.75-2x.04+0.15 (overlap 41cm+4cmcover=45cm)

= 1.27m , take 6 Nos. dowel bars 60° apart.

=6Nosx1.27x1.58 = 12.40kg

(iii)            16mm dia vertical bars @ 1.58kg in column

L = 3.30+0.6+0.10+0.10 =4.10m, take 6 Nos bars at 60° apart.

6Nosx4.1x1.58 = 38.87Kg

    (iV)      10mm Dia bars @ 0.62kg in lateral ties

                 No.= 3.90/.15+1 = 27Nos.

                 L = πx.22+18x1.0 (18xd) = .88m

                 27Nosx0.88x0.62 = 14.73kg.

                     Total weight:   53.33+12.04+38.87+14.73 = 118.97kg

ABSTRACT :

1.     Earthwork in excavation in foundation:        3.32cum

2.     Cement concrete 1:4:8 in base:                       0.32cum

3.     R.C.C work 1:2:4: in footing excluding        1.804cum

Steel and it’s bending.

4.     R.C.C work 1:2:4: in column above Ground 0.307cum

 Level (G.L) excluding steel and it’s bending

5.     Steel reinforcing bars including bending-   118.97kg 

Centering & shuttering required:

(a)  Footing trapezoidal portion- 4Nos.x(2.00+0.35)/2xsloping height

= 4x1.175x 

=4x1.175x0.964

4.531 sqm

(b) Square portion above G.L up to plinth- =4Nos.x0.35x0.6

= 0.840 sqm

(c.) Circular portion above plinth-

   =πx0.3x3.3

=3.109sqm

Total= 4.531+0.84+3.109 = 8.48sqm

  

   

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RCC T Beam design example

Construct a reinforcement roof on 9.00 meter x 6.00 meter room having wall thickness 30 centimeter at four sides.The span of room is large so T beam is used. Drawing is given below.

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RCC T Beam design
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